One mole of an ideal gas at $27^{\circ} {C}$ is taken from ${A}$ to ${B}$ as shown in the given ${PV}$ indicator diagram. The work done by the system will be $......\times 10^{-1} \,{J}$
[Given : $R=8.3\, {J} /\,mole\,{K}, \ln 2=0.6931$ ] (Round off to the nearest integer)
JEE MAIN 2021, Medium
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Process of isothermal
$W=n R T \ln \left(\frac{V_{2}}{V_{1}}\right)$
$1 \times 8.3 \times 300 \times \ln 2$
$=17258 \times 10^{-1} {J}$
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