Let $\eta_{1}$ is the efficiency of an engine at $T _{1}=447^{\circ}\,C$ and $T _{2}=147^{\circ}\,C$ while $\eta_{2}$ is the efficiency at $T _{1}=947^{\circ}\,C$ and $T _{2}=47^{\circ}\,C$. The ratio $\frac{\eta_{1}}{\eta_{2}}$ will be.
JEE MAIN 2022, Medium
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