STD 11 - 4.2 Quadratic equations and inequations — JEE कक्षा 11 साइन्स — Question

$ \Rightarrow {x^2} - 4x + 4 - x + 2 - 6 = 0$$ \Rightarrow $ ${x^2} - 5x = 0$

$ \Rightarrow $ $x(x - 5) = 0$ $ \Rightarrow $ $x = 0$

जब $x \ge 2$;  ${(x - 2)^2} + (x - 2)\, - 6 = 0$

$ \Rightarrow {x^2} - 4x + 4 + x - 2 - 6 = 0$

$ \Rightarrow $ ${x^2} - 3x - 4 = 0$

$ \Rightarrow $ ${x^2} - 4x + x - 4 = 0$

$ \Rightarrow $ $(x - 4)(x + 1) = 0$ 

$ \Rightarrow $ $x = 4$.