\(\log \frac{{{P_2}}}{{{P_1}}} = \frac{{\Delta {H_V}}}{{2.303R}}\left[ {\frac{{{T_2} - {T_1}}}{{{T_1} \times {T_2}}}} \right]\) \(\log \frac{{760}}{{23}} = \frac{{40656}}{{2.303 \times 8.314}}\left[ {\frac{{373 - {T_1}}}{{373T}}} \right]\)
This gives \({T_1} = 294.4\,K\).
આણ્વિય દળ ${K}=39, {Mn}=55, {O}=16]$
[આપેલ $K_b (H_2O) = 0.52\, K\, kg\, mol^{-1}]$