Number of turns in primary coil, \(n_1=4000\)
Output voltage, \(V _{2}=230 \,V\)
Number of turns in secondary coil \(= n _{2}\)
Voltage is related to the number of turns as:
\(\frac{V_{1}}{V_{2}}=\frac{n_{1}}{n_{2}}\)
\(\frac{2300}{230}=\frac{4000}{n_{2}}\)
\(n_{2}=\frac{4000 \times 230}{2300}=400\)
Hence, there are \(400\) turns in the second winding.