Plate resistance of two triode valves is 2 k Omega and 4 k Omega, amplification factor of each of the valves is 40. The ratio

Q: Plate resistance of two triode valves is $2 k \Omega$ and $4 k \Omega$, amplification factor of each of the valves is $40.$ The ratio of voltage amplification, when used with $4 k \Omega$ load resistance, will be

Voltage amplification $A_v=\frac{\mu}{1+\frac{r_p}{R_L}}=\frac{\mu R_L}{R_L+r_p}$ $\Rightarrow \frac{A_1}{A_2}=\frac{2+4}{4+4}=\frac{3}{4}$

MCQ

CBSE - English Medium

Plate resistance of two triode valves is $2 k \Omega$ and $4 k \Omega$, amplification factor of each of the valves is $40.$ The ratio of voltage amplification, when used with $4 k \Omega$ load resistance, will be

A$10$
B$\frac{4}{3}$
C$\frac{3}{4}$
D$\frac{16}{3}$

STD 12 Science
JEE physics
Electronics
NCERT

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