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Potential difference $(\triangle\text{V})$ between two points $A$ and $B$ separated by a distance $x,$ in a uniform electric field $E$ is given by $\triangle\text{V}=-\text{Ex},$ where xis measured parallel to the field lines. If a charge $q_0$ moves from $P$ to $Q,$ the change in potential energy $(\triangle\text{U})$ is given as $\triangle\text{U}=-\text{q}_0\triangle\text{V}.$ A proton is released from rest in uniform electric field of magnitude $4.0 \times 10^8Vm^{-1}$ directed along the positive $X-$ axis. The proton undergoes a displacement of $0.25m$ in the direction of $E$. Mass of a proton $= 1.66 \times 10^{-27}kg$ and charge of proton $ = 1.6 \times 10^{-19}C$.

1. The change in electric potential of the proton between the points $A$ and $B$ is:

1. The potential energy of proton decreases.
2. The potential energy of proton increases.
3. The proton loses kinetic energy.

As the proton moves from $P$ to $Q,$ then:

1. $-1.1J$
2. $2J$
3. $2.5J$
4. $3J$

If a system consistsoftwocharges $4mC$ and $-3mC$ with no external field placed at $(-5\ cm, 0, 0)$ and $(5\ cm, 0, 0)$ respectively.The amount of work required to separate the two charges infinitely away from each other is:

1. $1.56 \times 10^{-14}J$
2. $5.5 \times 10^{-14}J$
3. $2.56 \times 10^{-14}J$
4. $4.56 \times 10^{-14}J$

The mutual electrostatic potential energy between two protons which are at a distance of $9 \times 10^{-15}m, in _{92}U^{235 }$ nucleus is:

1. $1.6 \times 10^{11}J$
2. $0.5 \times 10^{23}J$
3. $-1.6 \times 10^{-11}J$
4. $3.2 \times 10^{22}J$

The change in electric potential energy of the proton for displacement from $A$ to $B$ is:

1. $-1 \times 10^8V$
2. $1 \times 10^8V$
3. $6.4 \times 10^{-19}V$
4. $-6.4 \times 10^{-19}V$

Total energy of the proton increases.