a
\(I _{ ms } V _{ rms }= P\)

\(I _{ ms } \times 200=100\)

\(I _{ ms }=\frac{1}{2}\)

So, \(I _{\text {peak }}= I _{ rms } \sqrt{2}\)

\(=\frac{1}{2} \times \sqrt{2}\)

\(=\frac{1}{\sqrt{2}}=0.707\,A\)