The time taken for the concentration to change from \(0.1 M\) to \(0.025 M\) is equal to two half lives, i.e., \(2×15=30\) minutes.
This is because when the concentration changes from \(0.1 M\) to \(0.025 M\), it is reduced to one fourth.
$\mathrm{N}_{2}(\mathrm{g})+3 \mathrm{H}_{2}(\mathrm{g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{g})$
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