\([N_2O_5]\) left \(=\,1.0-0.2\,=\,0.8\,mol\,L^{-1}\)
Rate of reaction \(=\,k\times [N_2O_5]\)
\(=\,3.0\times 10^{-4}\times 0.8\)
\(=\,2.4\times 10^{-4}\,mol\,L^{-1}\,s^{-1}\)
Rate of formation of \(NO_2\)
\(=\,4\times 2.4\times 10^{-4}\,=\,9.6\times 10^{-4}\,mol\,L^{-1}\,s^{-1}\)
| Run | $[A]/mol\,L^{-1}$ | $[B]/mol\,L^{-1}$ | $D$ ઉત્પન્ન થવાનો શરૂઆતનો દર $mol\,L^{-1}\,min^{-1}$ |
| $I.$ | $0.1$ | $0.1$ | $6.0 \times 10^{-3}$ |
| $II.$ | $0.3$ | $0.2$ | $7.2 \times 10^{-2}$ |
| $III.$ | $0.3$ | $0.4$ | $2.88 \times 10^{-1}$ |
| $IV.$ | $0.4$ | $0.1$ | $2.40 \times 10^{-2}$ |
ઉપરની વિગત પરથી નીચેનામાંથી ક્યું સાચુ છે ?
|
ક્રમ. |
$[A]_0$ |
$[B]_0$ |
વેગ $($મોલ $s^{-1}$) |
|
$(1)$ |
$0.50$ |
$0.50$ |
$1.6 \times {10^{ - 4}}$ |
|
$(2)$ |
$0.50$ |
$1.00$ |
$3.2 \times {10^{ - 4}}$ |
|
$(3)$ |
$1.00$ |
$1.00$ |
$3.2 \times {10^4}$ |
ઉપરોક્ત માહિતીને અનુરૂપ વેગ નિયમ શું છે?
( $\mathrm{R}=8.314 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}, \log 4=0.6021$ આપેલ છે.)
| $[A] (mol\,L^{-1})$ | $[B] (mol\,L^{-1})$ | પ્રક્રિયાનો પ્રારંભિક વેગ $(mol\, L^{-1}\,s^{-1} )$ |
| $0.05$ | $0.05$ | $0.045$ |
| $0.10$ | $0.05$ | $0.090$ |
| $0.20$ | $0.10$ | $0.72$ |
| No | $[NH_4^+]$ | $[NO_2^-]$ | rate of reaction |
| $1.$ | $0.24\, M$ | $0.10\, M$ | $7.2 \times {10^{ - 6}}$ |
| $2.$ | $0.12\, M$ | $0.10\, M$ | $3.6 \times {10^{ - 6}}$ |
| $3.$ | $0.12\, M$ | $0.15\, M$ | $5.4 \times {10^{ - 6}}$ |