Question
Put the given fraction in ascending order by making denominator equal:
$\frac{5}{6}, \frac{7}{8}, \frac{11}{12} \text { and } \frac{3}{10}$
$\frac{5}{6}, \frac{7}{8}, \frac{11}{12} \text { and } \frac{3}{10}$
✓
Answer
$ \frac{5}{6}, \frac{7}{8}, \frac{11}{12} \text { and } \frac{3}{10} $
L.C.M. of denominators $6,8,12$ and $10=240$
$ \begin{aligned} & \therefore \frac{5}{6}=\frac{5 \times 40}{6 \times 40}=\frac{200}{240} \\ & \frac{7}{8}=\frac{7 \times 30}{8 \times 30}=\frac{210}{240} \\ & \frac{11}{12}=\frac{11 \times 20}{12 \times 20}=\frac{220}{240} \\ & \frac{3}{10}=\frac{3 \times 24}{10 \times 24}=\frac{72}{240} \end{aligned} $
It is clear from the above that
$ \begin{aligned} & \frac{72}{240}<\frac{200}{240}<\frac{210}{240}<\frac{220}{240} \\ & \text { or } \frac{3}{10}<\frac{5}{6}<\frac{7}{8}<\frac{11}{12} \end{aligned} $
Hence, $\frac{3}{10}, \frac{5}{6}, \frac{7}{8}$ and $\frac{11}{12}$ are in ascending order.
L.C.M. of denominators $6,8,12$ and $10=240$
$ \begin{aligned} & \therefore \frac{5}{6}=\frac{5 \times 40}{6 \times 40}=\frac{200}{240} \\ & \frac{7}{8}=\frac{7 \times 30}{8 \times 30}=\frac{210}{240} \\ & \frac{11}{12}=\frac{11 \times 20}{12 \times 20}=\frac{220}{240} \\ & \frac{3}{10}=\frac{3 \times 24}{10 \times 24}=\frac{72}{240} \end{aligned} $
It is clear from the above that
$ \begin{aligned} & \frac{72}{240}<\frac{200}{240}<\frac{210}{240}<\frac{220}{240} \\ & \text { or } \frac{3}{10}<\frac{5}{6}<\frac{7}{8}<\frac{11}{12} \end{aligned} $
Hence, $\frac{3}{10}, \frac{5}{6}, \frac{7}{8}$ and $\frac{11}{12}$ are in ascending order.
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