b
Since \(\omega\) is constant, \(v\) would also be constant. So, no net force or torque is acting on ring. The force experienced by any particle is only along radial direction, or we can say the centripetal force.
The force experienced by inner part, \(F_{1}=m \omega^{2} R_{1}\)
The force experienced by outer part, \(F_{2}=m \omega^{2} R_{2}\)
\(\frac{F_{1}}{F_{2}}=\frac{R_{1}}{R_{2}}\)
