MCQ
Rearrange the following ( $I$ to $IV$ ) in the order of increasing masses
$(I)\,0.5$ mole of $O_3$
$(II)\,0.5\,gm$ atoms of oxygen
$(III)\,3.011 \times 10^{23}$ molecules of $O_2$
$(IV)\,5.6$ litre of $CO_2$ at $STP$
  • $II < IV < III < I$
  • B
    $II < I < IV < III$
  • C
    $IV < II < III < I$
  • D
    $I < II < III < IV$

Answer

Correct option: A.
$II < IV < III < I$
a
$(I)$ $0.5$ mole $\mathrm{O}_{3}=24\, \mathrm{g} \,\mathrm{O}_{3}$

$(II)$ $0.5$ $g$ atoms of oxygen $=8\, \mathrm{g}$

$(III)$ $\frac{3.011 \times 10^{23}}{6.022 \times 10^{23}} \times 32=16 \,\mathrm{g}\, \mathrm{O}_{2}$

$(IV)$ $\frac{5.6}{22.4} \times 44\, \mathrm{g} \,\mathrm{CO}_{2}=11 \,\mathrm{g}\, \mathrm{CO}_{2}$

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