- ✓$1.89$
- B$4$
- C$1$
- D$3$
$\therefore$ Distance between first two dark bands on each side of central maximum is the width of central maximum
$=2 x=\frac{2 \lambda D}{d}$
$=\frac{2 \times 5.4 \times 10^{-7} \times 1.4}{8 \times 10^{-4}}$
$=1.89 \times 10^{-3} m =1.89 mm$
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Reason : The output voltage and the input voltage of the diode have $180^o$ phase difference.

$1.$ The phase space diagram for a ball thrown vertically up from ground is
mcq $Image$
$2.$ The phase space diagram for simple harmonic motion is a circle centered at the origin. In the figure, the two circles represent the same oscillator but for different initial conditions, and $E_1$ and $E_2$ are the total mechanical energies respectively. Then $Image$
$(A)$ $ E_1=\sqrt{2} E_2$ $(B)$ $ E_1=2 E_2$
$(C)$ $ E_1=4 E_2$ $(D)$ $ E_1=16 E_2$
$3.$ Consider the spring-mass system, with the mass submerged in water, as shown in the figure. The phase space diagram for one cycle of this system is $Image$
mcq $Image$
Give the answer question $1,2$ and $3.$
