આપેલ : $\Delta H _{ f }{ }^\theta\left( Al _2 O _3\right)=-1700\,kJ\,mol ^{-1}$
$\Delta H _{ f }{ }^\theta\left( Fe _2 O _3\right)=-840\,kJ\,mol ^{-1}$
$Fe , Al$ અને $O$ નું મોલર દળ અનુક્રમે $56,27$ અને $16\,g\,mol ^{-1}$.
Molar mass $160\,g \quad 27\,g$
$\left(\Delta H _{ f }^0\right)_{\text {reaction }}=\left[\left(\Delta H _{ f }^0\right)_{ Al _2 O _3}+2\left(\Delta H _{ f }^0\right)_{ Fe }\right]- \left[\left(\Delta H _{ f }^0\right)_{ Fe _2 O _3}+2\left(\Delta H _{ f }^0\right)_{ Al }\right]$
$=[-1700+0]-[-840+0]$
$=-860\,kJ / mol$
$\text { Total mass of mixture }= Fe _2 O _3+ Al (1: 2 \text { molar }$
$\text { ratio })$
$=160+2 \times 27$
$=214\,g / mol$
$\text { Heat evolved per gram }=\frac{860}{214}=4\,kJ / g$
$\Delta H \,(kJ/mol)$ | |
$\frac 12 A \rightarrow B$ | $+150$ |
$3B \rightarrow 2C + D$ | $-125$ |
$E + A \rightarrow 2D$ | $+350$ |
$\Delta {U_{BC}} = - 5\,kJ\,mo{l^{ - 1}},{q_{AB}} = 2\,kJ\,mo{l^{ - 1}}$
$\Delta {W_{AB}} = - 5\,kJ\,mo{l^{ - 1}},{W_{CA}} = 3\,kJ\,mo{l^{ - 1}}$
$CA$ પ્રક્રમ દરમિયાન પ્રણાલી દ્વારા શોષાતી ઉષ્મા ......$kJ\,mo{l^{ - 1}}$