\(\mathrm{Rb}=[\mathrm{Kr}] 5 \mathrm{s}^{1}\)
Hence, the quantum numbers for \(5 s^{1}\) electron is given by
\(n=5, l=0, m=0, s=+\frac{1}{2} \text { or }-\frac{1}{2}\)
$A.$ $n =3, l =0, m =0$
$B.$ $n =4, l =0, m =0$
$C.$ $n =3, l =1, m =0$
$D.$ $n =3, l =2, m =1$
ક્રમ માટે સાયો વિકલ્પ શોધો :
$(d) n = 3, l = 2, m = 1\, (e) n = 3, l = 2, m = 0$
( $m= 1.67 \times 10^{-27}\, kg, h = 6.63 \times 10^{-34}\, J\,s$)