\(\therefore\) calculated enthaly of hydrogenation of benzene \(=3 \times(-119)\)
\(=-357 \mathrm{kJ} / \mathrm{mol}\)
Resonance energy of benzene \(=\Delta \mathrm{H}_{\mathrm{Exp}}-\Delta \mathrm{H}_{\mathrm{cal}}\)
\({-150=-357-\Delta \mathrm{H_{cal}}}\)
\({\Delta \mathrm{H}_{\mathrm{cal}}=-207 \;\mathrm{kJ} / \mathrm{mol}}\)
Enthalpy of hydrogenation of benzene \(=-207\; \mathrm{kJ} / \mathrm{mol}\)
$(A)$ $\Delta U = q + p \Delta V$
$(B)$ $\Delta G =\Delta H - T \Delta S$
$(C)$ $\Delta S =\frac{ q _{ rev }}{ T }$
$(D)$ $\Delta H =\Delta U -\Delta nRT$
નીચે આપેલા વિકલ્પોમાંથી યોગ્ય ઉત્તર પસંદ કરો.
$CO_{2(g)}$ અને $H_2O$ ના $\Delta H_f$ અનુક્રમે $-395$ અને $ -286$ $kJ \,mol^{-1}$ છે........$KJ$