MCQ
$(\sec A + \tan A - 1)(\sec A - \tan A + 1) - 2\tan A = $
- A$\sec A$
- B$2\sec A$
- ✓$0$
- D$1$
$ = ({\sec ^2}A - {\tan ^2}A) + \sec A + \tan A - \sec A$$ + \tan A - 1 - 2\tan A = 0$
$( \because {\sec ^2}A - {\tan ^2}A = 1)$
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