$A \rightarrow$ Product ;
given $t_{1 / 2}=1\,hr$
for a zero order reaction
$t_{\text {completion}}=\frac{\left[A_{0}\right]}{k}=\frac{\text {initial} \,\operatorname{conc}}{rate\, {\text{on}}\,{\text{ stant}}}$
$\therefore $ $t_{1 / 2}=\frac{\left[A_{0}\right]}{2 K}$
or $ k=\frac{\left|A_{0}\right|}{2 t_{1 / 2}}=\frac{2}{2 \times 1}=1\,mol\,lit$ $^{-1}\, h r^{-1}$
Further for a zero order reaction
$k=\frac{d x}{d t}=\frac{\text { change in concentration }}{\text {time}}$
$I=\frac{0.50-0.25}{time}$
$\therefore $ time $=0.25\, h r$
$\frac{d[NH_3]}{dt} = 2 \times 10^{-4} \, mol \,L^{-1} \, s^{-1}$ હોય, તો $\frac{-d[H_2]}{dt}$ ની કિંમત ............. $mol \,L^{-1} \, s^{-1}$ થશે.
તબક્કો $: I :$ $2A $ $\rightleftharpoons$ $ X $ ઝડપી.
તબક્કો $II :$ $X + B $ $\rightleftharpoons$ $Y$ ધીમી
તબક્કો $III :$ $Y + B$ નીપજ ઝડપી આખી પ્રક્રિયા કયા નિયમ પર આધારિત છે ?
[આપેલ: $\ln 10=2.3$$R =8.3\, J \, K ^{-1}\, mol ^{-1}$]