MCQ
સીમિત શકય ઉકેલ પ્રદેશના શિરોબિંદુઓ $A(3,3), B(20,3), C(20,10), D(18,12)$ અને $E(12, 12)$ છે હેતુલક્ષી વિધેય $Z=2 x+3 y$ ની મહાતમ કિમત મેળવો
- ✓$72$
- B$80$
- C$82$
- D$70$
Corner point Corresponding value
$\begin{array}{ll} & \text { of } \mathrm{Z}=2 x+3 y \\\mathrm{A}(3,3) & \mathrm{Z}=15 \\\mathrm{B}(20,3) & \mathrm{Z}=49 \\\mathrm{C}(20,10) & \mathrm{Z}=70 \\\mathrm{D}(18,12) & \mathrm{Z}=72 \\\mathrm{E}(12,12) & \mathrm{Z}=60\end{array}$
he maximum value of $\mathrm{Z}$ is $72.$
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