^ -1 ( 7 6 )+ ^ -1 ( 13 6 )= _______________ - Vidyadip

MCQ

$
\sin ^{-1}\left(\sin \frac{7 \pi}{6}\right)+\cos ^{-1}\left(\cos \frac{13 \pi}{6}\right)=
$ _______________

A
$\frac{\pi}{3}$
B
$-\frac{\pi}{3}$
C
$-\frac{\pi}{6}$
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0

✓

Answer

Correct option: D.

0

(D) 0
$\begin{array}{l}\sin ^{-1}\left(\sin \frac{7 \pi}{6}\right)+\cos ^{-1}\left(\cos \frac{13 \pi}{6}\right) \\ =\sin ^{-1}\left(\sin \left(\pi+\frac{\pi}{6}\right)\right)+\cos ^{-1}\left(\cos \left(2 \pi+\frac{\pi}{6}\right)\right) \\ =\sin ^{-1}\left(-\sin \frac{\pi}{6}\right)+\cos ^{-1}\left(\cos \frac{\pi}{6}\right) \\ =-\frac{\pi}{6}+\frac{\pi}{6}=0\end{array}$

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