MCQ
${\sin ^2}\frac{\pi }{8} + {\sin ^2}\frac{{3\pi }}{8} + {\sin ^2}\frac{{5\pi }}{8} + {\sin ^2}\frac{{7\pi }}{8} = $
- A$1$
- B$-1$
- C$0$
- ✓$2$
$ = {\sin ^2}\frac{\pi }{8} + {\sin ^2}\frac{{3\pi }}{8} + {\sin ^2}\frac{{3\pi }}{8} + {\sin ^2}\frac{\pi }{8}$
$ = 2\left( {{{\sin }^2}\frac{\pi }{8} + {{\sin }^2}\frac{{3\pi }}{8}} \right) = 2 \times 1 = 2$.
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