MCQ
${\sin ^2}x$ નું ${\cos ^2}x$ ની સાપેક્ષે વિકલન મેળવો.
- A${\tan ^2}x$
- B$\tan x$
- C$ - \tan x$
- ✓એકપણ નહીં
==> $\frac{{dy}}{{dx}} = \sin 2x$ and $\frac{{dz}}{{dx}} = - \sin 2x$,
$\therefore$ $\frac{{dy}}{{dz}} = - 1$.
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