If $4 \times {10^{20}}eV$ energy is required to move a charge of $0.25$ coulomb between two points. Then what will be the potential difference between them......$V$
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(b) By using, $KE = QV ==> 4 × 10^{20} × 1.6× 10^{-19}$
$= 0.25 × V ==> V = 256\, volt$
$= 0.25 × V ==> V = 256\, volt$
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