MCQ
સમીકરણ $|x - 2|^2 + |x - 2| - 6 = 0$ નાં બીજ ......છે.
- A$0, 4$
- B$-1, 3$
- C$4, 2$
- D$5, 1$
$ \Rightarrow {x^2} - 4x + 4 - x + 2 - 6 = 0$
$ \Rightarrow \,\,{x^2} - 5x = 0$
$ \Rightarrow \,\,x(x - 5) = 0$ $ \Rightarrow \,\,x = 0$
જ્યારે $,\,x \ge 2\,;$ ${(x - 2)^2} + (x - 2)\, - 6 = 0$
$ \Rightarrow {x^2} - 4x + 4 + x - 2 - 6 = 0$
$ \Rightarrow \,\,{x^2} - 3x - 4 = 0$
$ \Rightarrow \,\,{x^2} - 4x + x - 4 = 0$
$ \Rightarrow \,(x - 4)(x + 1) = 0$
$ \Rightarrow \,x = 4$
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