\(=-\frac{d({{O}_{2}})}{dt}=\frac{1}{2}\frac{d(S{{O}_{3}})}{dt}\)
\( - \,\frac{{d({O_2})}}{{dt}}\,\, = \,\,2.5\,\, \times \,\,{10^{ - 4}}\)
\(-\frac{d(S{{O}_{2}})}{dt}=2\times \frac{-d({{O}_{2}})}{dt}\) \(=2\times 2.5\times {{10}^{-4}}=\) \(5\times {{10}^{-4}}\,mol\,{{L}^{-1}}\,{{S}^{-1}}\)
$2MnO_4^ - + 10{I^ - } + 16{H^ + } \to 2M{n^{2 + }} + 5{I_2} + 8{H_2}O$ તો $I_2$ ના ઉત્પન્ન થવાનો દર......$\times {10^{ - 2}}\,M{s^{ - 1}}$ જણાવો