Question
Solve the following quadratic equation by factorisation:
$9x^2 - 3x - 2 = 0$
$9x^2 - 3x - 2 = 0$
✓
Answer
The given quadratic equation is
$9 x^2-3 x-2=0 \\ \Rightarrow 9 x^2-6 x+3 x-2=0$
$ \Rightarrow 3 x(3 x-2)+1(3 x-2)=0$
$\Rightarrow(3 x-2)(3 x+1)=0 $
$ \Rightarrow 3 x-2=0 \text { or } 3 x+1=0$
$ \Rightarrow 3 x=2 \text { and } 3 x=-1 $
$ \Rightarrow x=\frac{2}{3} \text { and } x=-\frac{1}{3} .$
$9 x^2-3 x-2=0 \\ \Rightarrow 9 x^2-6 x+3 x-2=0$
$ \Rightarrow 3 x(3 x-2)+1(3 x-2)=0$
$\Rightarrow(3 x-2)(3 x+1)=0 $
$ \Rightarrow 3 x-2=0 \text { or } 3 x+1=0$
$ \Rightarrow 3 x=2 \text { and } 3 x=-1 $
$ \Rightarrow x=\frac{2}{3} \text { and } x=-\frac{1}{3} .$
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