Question
Solve:
$x^4-1$

Answer

$x^4-1$
$=\left(x^2\right)^2-1$
$=\left(x^2+1\right)\left(x^2-1\right)$
$=\left(x^2+1\right)\left(x^2-1\right)$
$=\left(x^2+1\right)(x+1)(x-1)$

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