MCQ
$\sqrt 2 + \sqrt 3 + \sqrt 4 + \sqrt 6 = . . ..$
- ✓$\cot 7\frac{{{1^o}}}{2}$
- B$\sin 7\frac{{{1^o}}}{2}$
- C$\sin \,{15^o}$
- D$\cos \,\,{15^o}$
$= \frac{{2{{\cos }^2}A}}{{2\sin A\cos A}} = \frac{{1 + \cos 2A}}{{\sin 2A}}$
Putting $A = 7\frac{{{1^o}}}{2} $
$\Rightarrow \cot 7\frac{{{1^o}}}{2} = \frac{{1 + \cos {{15}^o}}}{{\sin {{15}^o}}}$
On simplification, we get
$\cot 7\frac{{{1^o}}}{2} = \sqrt 6 + \sqrt 2 + \sqrt 3 + \sqrt 4 $.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| $x_i$ | $0$ | $1$ | $5$ | $6$ | $10$ | $12$ | $17$ |
| $f_i$ | $3$ | $2$ | $3$ | $2$ | $6$ | $3$ | $3$ |