$\theta = 45^\circ $ and $n = 2$ (Given)
$\therefore \mu = \tan 45^\circ \left( {1 - \frac{1}{{{2^2}}}} \right) = 1 - \frac{1}{4} = \frac{3}{4} = 0.75$
(considering $4\ kg$ block doesn't fall on ground)
Consider the following statements
$(i)$ Time when relative motion between them is stopped is $1.4\ second$.
$(ii)$ Time when relative motion between them is stopped in $1.2\ second$
$(iii)$ The common velocity of the two blocks is $8\ m/s$, towards right.
$(iv)$ The displacement of the $4\, kg$ block when relative motion stopped is$10.8\ m$.
Which of the fstatements is/are correct

