$\left[g=10 m / s ^{2}\right]$.
\(N = mg\)
\(\Rightarrow 60 \times 10=600 N\)
When lift moves with downward acceleration.
In frame of lift pseudo force will be in upward direction.
\(N^{\prime}=M(g-a)\)
\(\Rightarrow 60(10-1.8)\)
\(N^{\prime} \Rightarrow 492 N\)