\(\lambda  = \frac{{6.6 \times {{10}^{ - 34}}}}{{\sqrt {2 \times 1.67 \times {{10}^{ - 27}} \times 1.88 \times {{10}^{ - 23}}T} }}\frac{{{P^2}}}{{2{m_n}}} = KT\)

\( \Rightarrow \,P = \sqrt {2{m_n}KT} \)

ઓરડાના તાપમાને \( = \,\,T\,\, = \frac{{6.6 \times {{10}^{ - 34}}}}{{\sqrt {4.6092 \times {{10}^{ - 52}}} \sqrt T }}\)

\( = \frac{{6.6 \times {{10}^{ - 34}} \times 1026}}{{\sqrt {4.6092} \sqrt T }} = \frac{{6.6 \times {{10}^{ - 8}}}}{{2.146 \times \sqrt T }} = \frac{{30.7}}{{\sqrt T }}{\rm{{}}} Å\)