\(\therefore \) Conc. after \(20\,min\) (two half lives) \(=\,2.5\,mol\,L^{-1}\)
Now, \(k\, = \,\frac{{0.693}}{{{t_{1/2}}}}\, = \,\frac{{0.693}}{{10\,\min }}\)
or \(0.0693\,min^{-1}\)
\(\therefore \) rate \(=\,k\times \) [reactant]
\(=\,0.0693\times 2.5\,\,mol\,L^{-1}\,min^{-1}\)
(આપેલું છે$: \ln 10=2.3, R =8.3 \,J\, K ^{-1} \,mol ^{-1}, \log 2=0.30$ )
No | $[NH_4^+]$ | $[NO_2^-]$ | rate of reaction |
$1.$ | $0.24\, M$ | $0.10\, M$ | $7.2 \times {10^{ - 6}}$ |
$2.$ | $0.12\, M$ | $0.10\, M$ | $3.6 \times {10^{ - 6}}$ |
$3.$ | $0.12\, M$ | $0.15\, M$ | $5.4 \times {10^{ - 6}}$ |
$\mathrm{N}_{2}(\mathrm{g})+3 \mathrm{H}_{2}(\mathrm{g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{g})$
સાચો વિકલ્પ કયો છે ?
$p ( mm Hg )$ | $50$ | $100$ | $200$ | $400$ |
સાપેક્ષ $t _{1 / 2}( s )$ | $4$ | $2$ | $1$ | $0.5$ |
પ્રક્રિયાનો ક્રમ શોધો.