MCQ
$\tan \left( {{{\tan }^{ - 1}}\frac{1}{2} - {{\tan }^{ - 1}}\frac{1}{3}} \right) = . . .$
- A$5/6$
- B$7/6$
- C$1/6$
- ✓$1/7$
$= \tan \left[ {{{\tan }^{ - 1}}\frac{{\frac{1}{2} - \frac{1}{3}}}{{1 + \frac{1}{6}}}} \right]$
$= \tan {\tan ^{ - 1}}\left( {\frac{1}{6} \times \frac{6}{7}} \right)$= $\frac{1}{7}$.
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