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Redox Reactions — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistryRedox Reactions5 Marks
Question
  1. $\text{Cu}|\text{Cu}^{2+}(1\text{M})||\text{Ag}^+(1\text{M})|\text{Ag}$
$\text{E}^0_\frac{\text{Cu}^{2+}}{\text{Cu}}=0.34\text{V}$

$\text{E}^0_\frac{\text{Ag}^+}{\text{Ag}}=+0.80\text{V}$
  1. Write reaction at anode and cathode.
  2. Write net cell reaction.
  3. Calculate e.m.f. of the cell.
  1. What is meant by E.M.F of cell? How is it measured?
✓

Answer

  1.  
  1. $\text{Cu}\text{(S)}\xrightarrow{ \ \ \ \ }\text{Cu}^{2+}\text{(aq)}+2\text{e}^-$ At anode
$2\text{Ag}^+\text{(aq)}+2\text{e}^-\xrightarrow{ \ \ \ \ \ \ }2\text{Ag}\text{(s)}$ At cathode
  1. $\text{Cu}\text{(s)}+2\text{Ag}^+\text{(aq)}\xrightarrow{ \ \ \ \ \ }\text{Cu}^{2+}\text{(aq)}+2\text{Ag(s)}$
$\text{E}^0_\text{cell}=\text{E}^0_\frac{\text{Ag}+}{\text{Ag}}-\text{E}^0_\frac{\text{Cu}^{2+}}{\text{Cu}}$

$=+0.80\text{V}-0.34\text{V}$

$=0.46\text{V}$
  1. It is equal to maximum potential difference when no current is drawn from the cell.

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