MCQ
The acceleration displacement graph of a particle executing $SHM$  is shown in figure. The time period of simple harmonic motion is
  • $\frac {4\pi }{\sqrt 3}\,s$
  • B
    $\frac {2\pi }{\sqrt 3}\,s$
  • C
    The given graph doesn't represent $SHM$
  • D
    Information is insufficient

Answer

Correct option: A.
$\frac {4\pi }{\sqrt 3}\,s$
a
$a=\omega^{2} x$

$\Rightarrow \frac{a}{x}=\omega^{2}=\tan 37^{\circ}=\frac{3}{4}$

$\Rightarrow \frac{4 \pi^{2}}{\mathrm{T}^{2}}=\frac{3}{4} \Rightarrow \mathrm{T}=\frac{4 \pi}{\sqrt{3}}$ $s$

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