MCQ
The acceleration due to gravity at a place is ${\pi ^2}\,m/se{c^2}$. Then the time period of a simple pendulum of length one metre is
  • A
    $\frac{2}{\pi }\,sec$
  • B
    $2\pi \,sec$
  • $2\,sec$
  • D
    $\pi \,sec$

Answer

Correct option: C.
$2\,sec$
c
$T = 2\pi \sqrt {\frac{l}{g}}  = 2\pi \sqrt {\frac{1}{{{\pi ^2}}}} = 2 \,sec$

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