The angle of $1^{\prime}$ (minute of arc) in radian is nearly equal to
A$1.75 \times 10^{-2} \;rad$
B$2.91 \times 10^{-4} \;rad$
C$4.85 \times 10^{-4} \;rad$
D$4.80 \times 10^{-6} \;rad$
NEET 2020, Easy
Download our app for free and get started
B$2.91 \times 10^{-4} \;rad$
b $\theta=1^{\prime}=\left(\frac{1}{60}\right)^{\circ}=\left(\frac{1}{60}\right) \frac{\pi}{180}$ radian
$=2.91 \times 10^{-4}$ radian
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Even if a physical quantity depends upon three quantities, out of which two are dimensionally same, then the formula cannot be derived by the method of dimensions. This statement
The dimensions of $\frac{\alpha}{\beta}$ in the equation $F=\frac{\alpha-t^2}{\beta v^2}$, where $F$ is the force, $v$ is velocity and $t$ is time, is ..........
In terms of resistance $R$ and time $T$, the dimensions of ratio $\frac{\mu } {\varepsilon }$ of the permeability $\mu $ and permittivity $\varepsilon $ is
If the speed of light $(c)$, acceleration due to gravity $(g)$ and pressure $(p)$ are taken as the fundamental quantities, then the dimension of gravitational constant is