MCQ
The average molar mass of chlorine is $35.5\, g$ $mol ^{-1}$. The ratio of $35\, Cl$ to $37 \,Cl$ in naturally occurring chlorine is close to :
- A$4:1$
- B$1:1$
- C$2:1$
- ✓$3:1$
let $\quad x \quad: \quad 1 \quad$ mass $=35.5$
mole ratio
Av. molar mass $=\frac{ n _{1} M _{1}+ n _{2} M _{2}}{\left( n _{1}+ n _{2}\right)}$
$35.5=\frac{x \times 35+1 \times 37}{x+1}$
$x=3$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$C{H_3} - C \equiv CH\xrightarrow[{(ii)\,\,NaB{H_4}}]{{(i)\,\,Hg{{(OAC)}_2}/{H_2}O}}\,(Q)$
Choose the correct option