The bob of a simple pendulum of mass m and total energy $E$ will have maximum linear momentum equal to
A$\sqrt {\frac{{2E}}{m}} $
B$\sqrt {2mE} $
C$2mE$
D$m{E^2}$
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B$\sqrt {2mE} $
b (b) ${p_{\max }} = \sqrt {2m\,{E_{\max }}} $
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