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The capacities of two conductors are ${C_1}$ and ${C_2}$ and their respective potentials are ${V_1}$ and${V_2}$. If they are connected by a thin wire, then the loss of energy will be given by
  • A$\frac{{{C_1}{C_2}({V_1} + {V_2})}}{{2({C_1} + {C_2})}}$
  • B$\frac{{{C_1}{C_2}({V_1} - {V_2})}}{{2({C_1} + {C_2})}}$
  • C$\frac{{{C_1}{C_2}{{({V_1} - {V_2})}^2}}}{{2({C_1} + {C_2})}}$
  • D$\frac{{({C_1} + {C_2})({V_1} - {V_2})}}{{{C_1}{C_2}}}$
Medium
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