c
Equivalent circuit
So change on $5\, \mu \mathrm{F}$ will be $+80\, \mu \mathrm{C}$
$\therefore $ Potential across $5 \mu \mathrm{F}=\frac{\mathrm{q}}{\mathrm{C}}=\frac{80 \times 10^{-6}}{5 \times 10^{-6}}=$$16 \mathrm{\,V}$
$\therefore $ Change on $3\, \mu \mathrm{F}=3 \times 10^{-6} \times 16=48\, \mu \mathrm{C}$
