Question
The concentration of hydrogen ion in a sample of soft drink is $3.8 \times 10^{-3} \mathrm{M}$. what is its pH ?

Answer

Given,
$[\text{H}^+]=3.8\times10^{-3}\text{M}$
$=-\log[\text{H}^+]$
$=-\log(3.8\times10^{-3})$
$=-\log3.8-\log10^{-3}$
$=-\log3.8+3$
$=-0.58+3$
$=2.42$

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