The resistance of a galvanometer is $25\, ohm$ and it requires $50\,\mu A$ for full deflection. The value of the shunt resistance required to convert it into an ammeter of $5\, amp$ is
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$S = \frac{G}{{\frac{i}{{{i_g}}} - 1}} = \frac{{25}}{{\frac{5}{{50 \times {{10}^{ - 6}}}} - 1}}$$ = \frac{{25}}{{{{10}^5} - 1}} = \frac{{25}}{{{{10}^5}}} = 2.5 \times {10^{ - 4}}\,\Omega $
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