The diameter of two pistons of a hydraulic press are $0.1\,\, m$ and $0.6\,\, m$ respectively. Advantage of the hydraulic press assuming effort is applied directly on pump plunger
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$Mech.$ $adv.$ $(MA)$
$=\frac{\text { Area of bigger piston }}{\text { Area of smaller piston }}$
$=\frac{\pi\left(\frac{\mathrm{d}_{1}}{2}\right)^{2}}{\pi\left(\frac{\mathrm{d}_{2}}{2}\right)^{2}}=\frac{\mathrm{d}_{1}^{2}}{\mathrm{d}_{2}^{2}}=\frac{0.36}{0.01}=36$
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