MCQ
The dimensions of $K$ in the equation $W = \frac{1}{2}\,\,K{x^2}$ is
- ✓${M^1}{L^0}{T^{ - 2}}$
- B${M^0}{L^1}{T^{ - 1}}$
- C${M^1}{L^1}{T^{ - 2}}$
- D${M^1}{L^0}{T^{ - 1}}$
✓
Answer
Correct option: A.
${M^1}{L^0}{T^{ - 2}}$
a
(a) $W = \frac{1}{2}k{x^2} \Rightarrow [k] = \frac{{[W]}}{{[{x^2}]}} = \left[ {\frac{{M{L^2}{T^{ - 2}}}}{{{L^2}}}} \right] = [M{T^{ - 2}}]$
(a) $W = \frac{1}{2}k{x^2} \Rightarrow [k] = \frac{{[W]}}{{[{x^2}]}} = \left[ {\frac{{M{L^2}{T^{ - 2}}}}{{{L^2}}}} \right] = [M{T^{ - 2}}]$
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