The displacement of a particle executing $S.H.M.$ is given by $x=0.01 \sin 100 \pi(t+0.05)$. The time period is ........ $s$
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(b)
$x=0.01 \sin 100 \pi(t+0.05)$
Here $\omega=100 \pi$
$T=\frac{2 \pi}{\omega}=\frac{2 \pi}{100 \pi}=\frac{1}{50}=0.02 \,s$
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