The distance between two consecutive points with phase difference of $60^{\circ}$ in a wave of frequency $500\,Hz$ is $6.0\,m$. The velocity with which wave is traveling is $.........km / s$
JEE MAIN 2023, Medium
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$\Delta \phi=\frac{2 \pi}{\lambda} \Delta x$
$\frac{\pi}{3}=\frac{2 \pi}{\lambda}(6 m )$
$\lambda=36\,m$
$V = f \lambda=(500\,Hz )(36\,m )$
$=18000\,m / s$
$=18\,km / s$
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