MCQ
The efficiency of a Carnot's engine working between steam point and ice point is:
- A26.81%
- B29%
- C30%
- D10%
✓
Answer
- 26.81%.
Explanation:
T1 = (100 + 273) = 373K
T2 = (0 + 273) = 273K
Efficiency $(\eta)=1-\frac{\text{T}_2}{\text{T}_1}$
$=1-\frac{273}{373}=\frac{100}{373}$
$\%\eta=\frac{100}{373}\times100=26.81\%$
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