Question
The enthalpy change for the reaction, $\text{Zn(s)}+2\text{H}^+(\text{aq})\overrightarrow{\ \ \ \ \ \ } \ \text{Zn}^{2+}(\text{aq})+\text{H}_2(\text{g}),$ is $-154.40 \mathrm{~kJ} \mathrm{~mol}^{-1}$. The formation of 2g of hydrogen expands the system by 22.4L at 1atm pressure.
What is the internal energy change of the reaction?

Answer

Taking the initial volume as negligible (as no gaseous reactant is present), change in volume during expansion $(\Delta\text{V})=22.4\text{L}.$External pressure $\left(\mathrm{P}_{\mathrm{ext}}\right)$ = 1atm$\Delta\text{H}=\Delta\text{U}+\text{p}\Delta\text{V}$
$\Delta\text{U}=\Delta\text{H}-\text{p}\Delta\text{V}$
$\text{p}\Delta\text{V}=1\text{atm}\times22.4\text{L}=22.4\text{L atm}$
$=22.4\times101.3\text{J}=2307\text{J}=2.31\text{kJ}$
$\therefore\Delta\text{U}=-154.4-2.31=-156.71\text{kJ}$

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